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=8.5in =11in

=0in =-1.75in


\begin{deluxetable}{cccccccccccc} \par\scriptsize\tablecolumns{12} \tablewidth{6... ...Kahabka {\it et al.} 1999; Kim -- Kim, S. {\it et al.} 1999. } \end{deluxetable}



John Hughes 2002-09-08